Comments on: How to calculate the quantity of water for a given concrete mix.?

By: Preet Chovatiya

Preet Chovatiya — Sat, 28 Nov 2020 13:41:29 +0000

As we know 1:2:4 ratio is for M15 concrete. Generally Water quantity is calculated as per below formula:

Water Quantity=W/C ratio*Cement Quantity

Generally W/C ratio is lays between 0.4 to 0.6 as per IS 10262(2009).

Now first we have to assume cement quantity, so let’s assume cement quantity=50 KG and W/C ratio=0.5

Now let’s calculate water quantity for 50 KG cement.

Water Quantity=0.5*50=25 liter.

By: Omprakash Dhawale

Omprakash Dhawale — Mon, 05 Oct 2020 14:05:29 +0000

Sir,

With reference to the IS10262-2019 code, for 10mm aggregate sizes, the water content is 208Kg/ meter cube. Refer the attached table.

By: rawaa

rawaa — Sun, 13 Sep 2020 15:49:15 +0000

it depend on the code of ACI 211.1-91

the water content depend on quantity of cement and many factors effect like size of aggregate and compressive strength that the concrete designed for.

By: Subash Pathak

Subash Pathak — Thu, 10 Sep 2020 18:29:15 +0000

1:2:4 i.e cement:sand: coarse aggregate ratio during the batching of concrete. for the quantity of water, first, find out cement content for the given volume.

lets cement content be x (kg)

then,

water requirement = x * 0.5 liters/ bag of cement

By: sanjaypakad

sanjaypakad — Mon, 07 Sep 2020 12:42:29 +0000

w/c ratio is the weight ratio of the quantity of water used and weight of cement used in a particular concrete mixture.

w/c ratio = (water weight)/(cement weight)

If you do not know what number to use for the (w/c) ratio, please refer to the standards (depending on the country you reside/ where you want to use the concrete) regarding the maximum limits on the w/c ratio.

By: aviratdhodare

aviratdhodare — Fri, 21 Aug 2020 07:54:48 +0000

To calculate the amount of water required for a concrete mix, we need to calculate the quantity of cement required. Assume the required amount of cement is 50kg Amount of water required = W/C ratio x cement required. = 0.5 x 50 =25 kg or 25 lit

M 15 grade concrete

Cement = 1 Part
Sand = 2 Part
Aggregate = 4 Part
Total dry volume of Material Required = 1.57 cu.m
1+2+4=7
Water cement ratio =0.45
Water /cement =0.45
Water = cement X 0.45
Cement is =322.56 kg
Water =322.56 X 0.45
Water =145 liter

By: shiv

shiv — Wed, 19 Aug 2020 10:46:27 +0000

Here we have 1:2:4 mix is given, which is the standard ratio for M15 grade.

I do the calculation for 1 m3 concrete.

for cement content, c= 1/(1+2+4)= 1/7 m3

weight of cement = {1/7/(.035)}*50 = 204kg

total weight of cement for mix = 1.54*204 = 310.20kg

(total weight of cement for mix =310.20kg) >( minimum cement content – 300kg for moderate exposure condition)

<(maximum cement comntent -450kg)

for exact water content, we should know about exposure conditions, for different exposure conditions water content will be different. here I mention different exposure conditions with their maximum w/c ratio.

mild-.55

moderate – .50

sever – .45

very sever – .45

extreme – .40

I do the calculation for moderate exposure condition (you can do it for others exposure condition also, but the method will be the same. for other calculation you should check cement content for minimum and maximum cement content with different exposure condition)

w/c = .50

w = .5*310.20

w = 155.10 kg = 155.10 liter

so, water content for m15 grade with moderate exposure is 155.10 liter.

By: shankar

shankar — Mon, 17 Aug 2020 03:05:01 +0000

Actually water content is determined from the W/c ratio of different mixes as per IS 456:2000. but roughly for normal mix (1:2:4), we can calculate as

vol. of cement = 0.0354 cu.m

vol. of C.A+ F.A=2*0.0354+4*0.0354=0.211 cu.m

Vol. of water = 11.67 litre for 1 bag + 5% of total aggregate

= 11.67+(0.05*0.211)*1000=11.67+10.55= 22.22 litre